HSCScienceExam practice
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Chemistry  ·  Year 12  ·  Module 5  ·  Lesson 13

HSC Exam Practice

Temperature & Keq, Colourimetry

10 questions / 3 sections / 32 marks total
Section 1

Short answer

1.Short answer

1.1

Define the equilibrium constant Keq and state the only factor that changes its numerical value.

2marks Band 3
1.2

Distinguish between the effect of temperature on the position of equilibrium and on the value of Keq.

3marks Band 3–4
1.3

Explain why increasing temperature causes Keq to decrease for the exothermic reaction:

N2(g) + 3H2(g) ⇌ 2NH3(g)   ΔH° = −92 kJ mol−1

3marks Band 4
1.4

State the Beer–Lambert law. Identify each variable and its units. Describe the relationship between absorbance and concentration it predicts.

3marks Band 3
1.5

Outline the steps used in a colourimetry experiment to determine Keq for the equilibrium Fe3+(aq) + SCN(aq) ⇌ FeSCN2+(aq).

4marks Band 4
1.6

Describe the qualitative relationship between ΔG° and Keq, with reference to a reaction where Keq >> 1 and one where Keq << 1.

3marks Band 4
Section 2

Data response

2.Data response — Keq vs temperature for N2O4 ⇌ 2NO2

2.1

The graph below shows how Keq (mol L−1) varies with temperature for the equilibrium N2O4(g) ⇌ 2NO2(g).

0.00 0.05 0.10 0.15 0.20 0.25 0.30 0.35 0.40 Kₚₓ (mol L⁻¹) 25 45 65 85 Temperature (°C) 0.0046 0.0218 0.0947 0.371
Figure 2.1. Keq vs temperature for N2O4(g) ⇌ 2NO2(g). Data: adapted from NIST Chemistry WebBook.

(a) Describe the trend shown in Figure 2.1. (1 mark)

(b) Use the data to determine whether the forward reaction is exothermic or endothermic. Justify your answer using Le Chatelier’s Principle. (2 marks)

(c) Estimate Keq at 100°C and justify whether it would be greater or less than 0.371. (1 mark)

4marks Band 4–5

3.Data response — colourimetry Keq calculation

3.1

A student prepares an equilibrium mixture for Fe3+(aq) + SCN(aq) ⇌ FeSCN2+(aq) at 25°C with the following initial concentrations: [Fe3+]0 = 3.00 × 10−3 mol L−1, [SCN]0 = 1.00 × 10−3 mol L−1. Using a calibration curve with equation A = 0.240c (c in 10−4 mol L−1), an absorbance of 0.576 is measured at equilibrium.

(a) Calculate [FeSCN2+]eq. (1 mark)

(b) Construct an ICE table and calculate [Fe3+]eq and [SCN]eq. (3 marks)

(c) Calculate Keq for this equilibrium at 25°C. (1 mark)

(d) State one assumption made in this calculation about the ICE table change row, and identify the physical reason this assumption holds for the iron thiocyanate system. (1 mark)

6marks Band 4–5
Section 3

Extended response

4.Source critique

4.1

A science communicator writes:

“Adding a catalyst to an equilibrium system at a fixed temperature will increase Keq, because the catalyst helps more product to form faster, pushing the equilibrium constant upward to reflect this new product-rich state.”

Identify the scientific flaw in this statement and explain the correct chemistry.

4marks Band 4–5

5.Extended response

5.1

Evaluate the use of colourimetry as a method for determining Keq in the iron(III) thiocyanate equilibrium system. In your response, refer to the principles underlying the method, a named Australian environmental or industrial application of related colourimetric analysis, and at least two limitations of the method.

7marks Band 5–6

Chemistry · Year 12 · Module 5 · Lesson 13

Answer Key & Marking Guidelines

1.1

Section 1 · Short answer · 2 marks · Band 3

Sample response. Keq is the ratio of the product of equilibrium concentrations of products to the product of equilibrium concentrations of reactants, each raised to the power of its stoichiometric coefficient, for a given reaction at a specified temperature. The only factor that changes the numerical value of Keq is temperature.

Marking notes. 1 mark for a correct definition of Keq (concentrations of products over reactants, raised to stoichiometric coefficients, at equilibrium); 1 mark for stating temperature as the only factor that changes Keq.

1.2

Section 1 · Short answer · 3 marks · Band 3–4

Sample response. The position of equilibrium refers to the relative concentrations of reactants and products present at equilibrium at a given temperature; it can be shifted by changes in concentration, pressure, or temperature. The value of Keq is a thermodynamic constant that depends only on temperature: it specifies what the ratio of concentrations will be at equilibrium at that temperature. Changing temperature changes Keq itself — a new equilibrium with a different ratio of product to reactant concentrations. Changing concentration or pressure shifts the position toward the existing equilibrium (Le Chatelier’s Principle) but the ratio at the new equilibrium is still Keq — unchanged.

Marking notes. 1 mark — defines position of equilibrium as relative concentrations; 1 mark — states Keq is the equilibrium ratio of concentrations, temperature-dependent only; 1 mark — explicitly contrasts that concentration/pressure changes shift position without changing Keq, while temperature changes Keq.

1.3

Section 1 · Short answer · 3 marks · Band 4

Sample response. The Haber process forward reaction (N2 + 3H2 → 2NH3) is exothermic (ΔH° = −92 kJ mol−1), meaning heat is effectively a product. Increasing temperature adds heat to the system, which by Le Chatelier’s Principle shifts the equilibrium to the left (toward reactants) to consume the excess heat. As a result, less NH3 is present at the new equilibrium and more N2 and H2 remain, so the numerator of the Keq expression decreases while the denominator increases — the value of Keq falls. At the thermodynamic level, increasing T increases TΔS°, making ΔG° = ΔH° − TΔS° less negative (more positive), which gives a smaller Keq via ΔG° = −RT ln Keq.

Marking notes. 1 mark — identifies forward reaction as exothermic / heat as product; 1 mark — applies Le Chatelier’s Principle correctly (equilibrium shifts left at higher T); 1 mark — links the shift to decreased [NH3]eq and therefore decreased Keq.

1.4

Section 1 · Short answer · 3 marks · Band 3

Sample response. Beer–Lambert law: A = εlc. A is absorbance (dimensionless); ε is molar absorptivity (L mol−1 cm−1); l is path length (cm); c is concentration (mol L−1). For fixed ε and l, A is directly proportional to c — a straight-line relationship through the origin, which is the basis of the calibration curve.

Marking notes. 1 mark — correct equation A = εlc; 1 mark — correctly identifies at least two variables with correct units; 1 mark — describes A directly proportional to c (linear through origin) for constant ε and l.

1.5

Section 1 · Short answer · 4 marks · Band 4

Sample response. (1) Prepare a series of calibration solutions with known [FeSCN2+] and measure their absorbance; plot absorbance vs [FeSCN2+] to obtain the calibration curve (straight line through origin). (2) Prepare an equilibrium mixture from known initial [Fe3+] and [SCN]; allow to reach equilibrium. (3) Measure the absorbance of the equilibrium mixture at the same wavelength; use the calibration curve to read [FeSCN2+]eq. (4) Construct an ICE table using initial concentrations and [FeSCN2+]eq to find [Fe3+]eq and [SCN]eq. (5) Substitute all equilibrium concentrations into the Keq expression and calculate Keq.

Marking notes. 1 mark each for any four of the five correctly sequenced steps. The steps need not be numbered but must be in logical order (calibration → equilibration → absorbance measurement → ICE table → Keq calculation).

1.6

Section 1 · Short answer · 3 marks · Band 4

Sample response. ΔG° = −RT ln Keq. When Keq >> 1 (e.g. Keq = 1040 for H2 + ½O2 → H2O): ln Keq is a large positive number, so ΔG° is a large negative value — products are strongly thermodynamically favoured and the forward reaction is highly spontaneous under standard conditions. When Keq << 1 (e.g. Keq = 10−30 for N2 + O2 → 2NO): ln Keq is large and negative, so ΔG° is large and positive — reactants are strongly favoured and the forward reaction is non-spontaneous.

Marking notes. 1 mark — states ΔG° = −RT ln Keq or correct qualitative form; 1 mark — correctly links Keq >> 1 to large negative ΔG° (products favoured, spontaneous); 1 mark — correctly links Keq << 1 to large positive ΔG° (reactants favoured, non-spontaneous). A named example for each is not required but strengthens the response.

2.1

Section 2 · Data response · 4 marks · Band 4–5

Part (a). Keq increases as temperature increases from 25°C to 85°C, with the increase accelerating at higher temperatures (the relationship is approximately exponential). Keq increases approximately 80-fold over the 60°C range.

Marking notes (a). 1 mark for correctly describing Keq increases with temperature. Award the mark if one specific value is quoted.

Part (b). The forward reaction is endothermic. Keq increases as temperature increases, meaning higher temperature produces more NO2 at equilibrium. By Le Chatelier’s Principle, adding heat to the system shifts the equilibrium in the direction that absorbs heat — i.e., toward the endothermic direction. Since equilibrium shifts to the right (toward NO2, products) when temperature increases, the forward reaction must be endothermic (ΔH° > 0).

Marking notes (b). 1 mark — identifies forward reaction as endothermic; 1 mark — applies Le Chatelier’s Principle correctly, linking increasing T to shift toward product and ΔH° > 0.

Part (c). Keq at 100°C would be greater than 0.371. The forward reaction is endothermic, so further increasing temperature beyond 85°C continues to increase Keq. Extrapolating the upward trend in Figure 2.1, Keq at 100°C would be substantially greater than 0.371 (likely in the range 0.6–1.0 based on the trend).

Marking notes (c). 1 mark for stating Keq > 0.371 AND giving a valid justification (forward reaction is endothermic / upward trend continues / Le Chatelier). The numerical estimate is not required.

3.1

Section 2 · Data response · 6 marks · Band 4–5

Part (a) — [FeSCN2+]eq (1 mark). A = 0.240c ⇒ c = 0.576/0.240 = 2.40 (in units of 10−4 mol L−1) = 2.40 × 10−4 mol L−1. 1 mark for correct value and units.

Part (b) — ICE table (3 marks).

Fe3+: I = 3.00×10−3, C = −2.40×10−4, E = 2.76×10−3 mol L−1.

SCN: I = 1.00×10−3, C = −2.40×10−4, E = 7.60×10−4 mol L−1.

FeSCN2+: I = 0, C = +2.40×10−4, E = 2.40×10−4 mol L−1.

1 mark: ICE table structure with correct change signs (Fe3+ and SCN decrease by equal amounts, FeSCN2+ increases by same amount — 1:1:1 stoichiometry); 1 mark: correct [Fe3+]eq; 1 mark: correct [SCN]eq.

Part (c) — Keq (1 mark). Keq = (2.40×10−4) / [(2.76×10−3)(7.60×10−4)] = (2.40×10−4) / (2.098×10−6) = 114 (accept 110–120 for rounding). 1 mark.

Part (d) — Assumption (1 mark). The assumption is that both Fe3+ and SCN decrease by the same amount as FeSCN2+ increases (1:1:1 stoichiometric change). This holds because the balanced equation for the equilibrium shows a 1:1:1 mole ratio: one mole of Fe3+ reacts with one mole of SCN to produce one mole of FeSCN2+.

4.1

Section 3 · Source critique · 4 marks · Band 4–5

Sample response. The scientific flaw is the claim that a catalyst increases Keq. A catalyst does not change Keq. Keq is determined by the thermodynamic stability of reactants relative to products (ΔG° = −RT ln Keq), which depends only on the nature of the substances and the temperature. A catalyst lowers the activation energy of both the forward and reverse reactions equally, so the rates of both reactions increase by the same factor. The system reaches equilibrium faster, but the equilibrium composition — and therefore Keq — is identical to that reached without a catalyst. While the catalyst does increase the rate of product formation, it equally increases the rate of the reverse reaction, so more product is not present at equilibrium — the statement confuses reaction rate with equilibrium position.

Marking notes. 1 mark — identifies the flaw (catalyst does not change Keq); 1 mark — explains that Keq depends only on temperature (ΔG° or thermodynamic stability of substances); 1 mark — explains that a catalyst lowers activation energy of both forward and reverse reactions equally; 1 mark — concludes that equilibrium composition (ratio of concentrations) is unchanged, distinguishing rate from equilibrium position.

5.1

Section 3 · Extended response · 7 marks · Band 5–6

Sample response. Colourimetry is an effective and widely used method for determining Keq in the iron(III) thiocyanate system. The method is based on Beer–Lambert law (A = εlc), which states that absorbance of light by a coloured solution is directly proportional to the concentration of the absorbing species for fixed path length and molar absorptivity. FeSCN2+ is intensely red, allowing its equilibrium concentration to be measured accurately from the absorbance of the equilibrium mixture, using a calibration curve constructed from standard solutions. The equilibrium concentrations of the colourless species (Fe3+ and SCN) are calculated by ICE table from the known initial concentrations and the measured [FeSCN2+]eq, then substituted into the Keq expression. This method is directly analogous to colourimetric techniques used in environmental monitoring: the NSW Environment Protection Authority uses absorption spectrophotometry to measure NO2 concentrations in ambient air, converting absorbance readings of a Griess-type coloured product into quantitative [NO2] values using a calibration curve — the same Beer–Lambert principle. Despite these strengths, the method has two important limitations. First, Beer–Lambert law assumes ideal dilute solution behaviour — at high concentrations, solute–solute interactions change ε and the A–c relationship becomes non-linear, causing [FeSCN2+]eq and therefore Keq to be inaccurate. Second, the calibration curve must be prepared at the same temperature as the equilibrium experiment, because ε is temperature-dependent; if the calibration is done at a different temperature, the gradient will not correctly represent the absorbance-to-concentration conversion at the experimental temperature, introducing systematic error in Keq. A third limitation is that the method is only applicable to equilibrium systems containing a coloured species — it cannot be directly applied to systems where all species are colourless. Overall, colourimetry provides a simple, rapid, and non-destructive means of determining Keq when a coloured species is present, and its limitations can be managed through careful calibration design.

Marking notes. 1 mark — correctly states Beer–Lambert law and applies it to FeSCN2+; 1 mark — describes the role of the calibration curve (absorbance → concentration); 1 mark — describes how [Fe3+]eq and [SCN]eq are obtained from the ICE table; 1 mark — names a specific Australian environmental or industrial colourimetric application (NSW EPA NO2 monitoring, or FSANZ food dye testing); 1 mark — first correctly described limitation; 1 mark — second correctly described limitation; 1 mark — overall evaluative statement that correctly qualifies the usefulness of the method (not just lists pros/cons but reaches a judgement). A response that lists only limitations without explaining the principles, or that lists principles without evaluating limitations, cannot score above 5.