Chemistry • Year 12 • Module 5 • Lesson 11

Consolidation — ICE Table Mastery

Lock in the vocabulary, structure, and rules of the ICE table method before tackling harder problems.

Build • Band 3–4

1. Term–definition match

Match each term to its correct definition. Write the matching term from this list in the right-hand column: ICE table, initial concentration, change row, equilibrium concentration, stoichiometric ratio, simplifying assumption, 5% rule, reaction quotient (Q), Keq, verification step. 10 marks

#DefinitionMatching term
1.1The concentration of each species at the exact moment of measurement after the system has reached equilibrium.
1.2A systematic layout of Initial, Change, and Equilibrium rows used to calculate equilibrium concentrations from initial conditions and Keq.
1.3The row in an ICE table that expresses how much each concentration changes, written in terms of x and using mole ratios from the balanced equation.
1.4The ratio of coefficients in the balanced chemical equation that determines how changes in one species relate to changes in all others.
1.5The approximation (Initial ± x) ≈ Initial, valid when x is very small relative to the initial concentration.
1.6The criterion that if x divided by the initial concentration is less than 5%, the simplifying assumption introduces acceptable error.
1.7A measure of the concentrations of products and reactants at any point that is compared to Keq to determine the direction of reaction.
1.8The concentration of each species before any reaction has occurred, placed in the first row of the ICE table.
1.9The equilibrium constant expressed in terms of molar concentrations of gaseous or aqueous species only.
1.10Substituting equilibrium concentrations back into the Keq expression to confirm the calculated answer is consistent with the given Keq.
Stuck? Revisit the Key Terms panel and Formula Panel in Lesson 11.

2. True or false — with correction

Circle T or F for each statement. If false, write the corrected version on the line provided. 10 marks (1 T/F + 1 correction where needed)

2.1 For the equilibrium N2(g) + 3H2(g) ⇌ 2NH3(g), the correct Change row is: N2: −x; H2: −x; NH3: +x.    T  /  F

2.2 Pure solids and pure liquids are included in the Keq expression because their concentrations change during the reaction.    T  /  F

2.3 If Q < Keq, the system must shift in the reverse direction to reach equilibrium.    T  /  F

2.4 For the equilibrium 2HI(g) ⇌ H2(g) + I2(g), if x mol/L of H2 is produced, then 2x mol/L of HI is consumed.

T  /  F

2.5 The simplifying assumption is always valid when Keq < 1.    T  /  F

Stuck? Revisit Cards 1, 3 and 4 of Lesson 11, and the Keq expression rules from Lesson 9.

3. Complete the ICE tables

Fill in every blank cell. The equilibrium for each problem is given below the table heading. 12 marks (2 per completed table row with correct stoichiometry)

Problem 3A — 1:1:1 ratio

PCl5(g) ⇌ PCl3(g) + Cl2(g). Initial: [PCl5] = 0.500 mol L−1; [PCl3] = [Cl2] = 0. Let x = change in [PCl3].

PCl5PCl3Cl2
Initial (mol L−1)0.50000
Change (mol L−1)+x
Equilibrium (mol L−1)x

Write the Keq expression using E-row values: Keq =

Problem 3B — 1:3:2 ratio (Haber process)

N2(g) + 3H2(g) ⇌ 2NH3(g). Initial: [N2] = 0.800, [H2] = 1.200, [NH3] = 0 mol L−1. Let x = decrease in [N2].

N2H2NH3
Initial (mol L−1)0.8001.2000
Change (mol L−1)−x
Equilibrium (mol L−1)

Write the Keq expression: Keq =

Problem 3C — Heterogeneous equilibrium

CaCO3(s) ⇌ CaO(s) + CO2(g). Initial: [CO2] = 0 mol L−1; CaCO3 and CaO are pure solids. Let x = increase in [CO2].

CaCO3(s)CaO(s)CO2(g)
Initialsolid (excluded)solid (excluded)0
Changeexcludedexcluded
Equilibriumexcludedexcluded

Explain in one sentence why CaCO3 and CaO are excluded from the Keq expression:

Write the Keq expression: Keq =

Stuck? Revisit the exclusion rule for heterogeneous equilibria from Lesson 9.

4. Fill-in-the-blank paragraph

Complete the paragraph using the word bank below. Each word is used exactly once. 8 marks

Word bank: quadratic, five, stoichiometric, positive, reverse, verify, equilibrium, quotient

When setting up an ICE table, the Change row must use ________ ratios from the balanced equation. If the initial concentrations of all species are non-zero, the reaction ________ (Q) must be calculated first to determine whether the system will shift in the forward or ________ direction. Once x is solved, all ________ concentrations (the E row) must be ________—that is, physically meaningful. The simplifying assumption is valid only if x / [initial] × 100 is less than ________ percent. When this threshold is exceeded, the ________ formula must be used. Finally, always ________ by substituting the E-row values back into the Keq expression.

Stuck? Revisit the Formula Panel and Lesson 11 Cards 1, 3 and 4.

5. Short recall questions

Answer each question in 1–2 sentences using precise chemical terms. 8 marks, 2 each

5.1 What does the value of Q compared to Keq tell you about the direction a system will shift?

5.2 Why must you check the 5% rule after solving for x, not just before applying the simplifying assumption?

5.3 A student obtains a negative equilibrium concentration in the E row. What does this indicate and what should they do?

5.4 State the most common error students make in the Change row of an ICE table and explain how to avoid it.

Stuck? Revisit Card 1 (Error Diagnosis), Card 3 (Funnel Analogy) and the Formula Panel in Lesson 11.
Answers — Do not peek before attempting

Q1 — Term–definition matches

1.1 equilibrium concentration • 1.2 ICE table • 1.3 change row • 1.4 stoichiometric ratio • 1.5 simplifying assumption • 1.6 5% rule • 1.7 reaction quotient (Q) • 1.8 initial concentration • 1.9 Keq • 1.10 verification step

Q2 — True / false with correction

2.1 False. Correct Change row: N2: −x; H2: −3x; NH3: +2x. (Stoichiometric coefficients must be used.)

2.2 False. Pure solids and pure liquids are excluded from the Keq expression because their concentrations are constant and are incorporated into the value of Keq.

2.3 False. If Q < Keq, the system shifts forward (toward products) to increase Q toward Keq.

2.4 True. The ratio 2HI : 1H2 means if H2 increases by x, HI decreases by 2x. Correct.

2.5 False. The simplifying assumption is valid only when Keq / [initial] < 5%. A small Keq does not guarantee this — e.g., Keq = 0.4 with [initial] = 0.5 gives 80%, which is invalid.

Q3A — PCl5 decomposition ICE table

Change: PCl5: −x; PCl3: +x; Cl2: +x. Equilibrium: PCl5: 0.500 − x; PCl3: x; Cl2: x. Keq = x × x / (0.500 − x) = x² / (0.500 − x).

Q3B — Haber process ICE table

Change: N2: −x; H2: −3x; NH3: +2x. Equilibrium: N2: 0.800 − x; H2: 1.200 − 3x; NH3: 2x. Keq = (2x)² / [(0.800 − x)(1.200 − 3x)³].

Q3C — Heterogeneous equilibrium

Change: CO2: +x. Equilibrium: CO2: x. Exclusion reason: Pure solids have a constant concentration that does not change during the reaction; their activity is defined as 1 and is incorporated into the numerical value of Keq. Keq = [CO2].

Q4 — Cloze paragraph

stoichiometric • quotient • reverse • equilibrium • positive • five • quadratic • verify

Q5.1

If Q < Keq, the system shifts forward (producing more products). If Q > Keq, the system shifts in reverse (consuming products). If Q = Keq, the system is already at equilibrium and no net shift occurs.

Q5.2

The pre-check (Keq / [initial]) is an estimate of whether x will be small, but it is not exact. After solving, you must confirm that the actual x satisfies x / [initial] < 5%; if it does not, the assumption was invalid and the problem must be re-solved using the quadratic formula.

Q5.3

A negative equilibrium concentration is physically impossible. It indicates an error—most likely the wrong direction of shift (wrong sign in the Change row) or a stoichiometric ratio error. The student should check Q vs Keq to confirm the direction, then redo the Change row.

Q5.4

The most common error is writing ±x for every species regardless of coefficients. To avoid it: always write out the balanced equation first and use the stoichiometric coefficients as multipliers for x in every Change row entry.