Chemistry • Year 11 • Module 4 • Lesson 1

Enthalpy & Energy Profile Diagrams

Develop HSC Band 5–6 extended-response and synthesis skills on enthalpy, energy profile diagrams, and thermochemical equations.

Master • Extended Response

1. Data + scenario — LNG processing and the energy landscape of combustion (Band 5–6)

8 marks   Band 5–6

Scenario. Engineers at a North West Shelf LNG facility near Karratha, Western Australia are evaluating two fuels for an emergency generator: methane (CH4) and propane (C3H8). Both combust in excess oxygen. The thermochemical data are shown below.

FuelCombustion equationΔH (kJ mol−1)Ea(fwd) (kJ mol−1)
Methane (CH4) CH4(g) + 2O2(g) → CO2(g) + 2H2O(l) −890 420
Propane (C3H8) C3H8(g) + 5O2(g) → 3CO2(g) + 4H2O(l) −2220 440
Methane combustion Reaction coordinate → Enthalpy Reactants Products Ea=420 ΔH=−890 Propane combustion Reaction coordinate → Enthalpy Reactants Products Ea=440 ΔH=−2220
Figure 1. Comparative energy profile diagrams for methane (left) and propane (right) combustion. Diagrams not to scale. Values from lesson thermochemical data.

Q1. Analyse and evaluate the thermochemical data and the energy profile diagrams to determine which fuel is more suitable for the Karratha emergency generator. In your response you must:

  • Define enthalpy change (ΔH) and state what its sign indicates about the direction of energy flow.
  • Compare the two fuels on at least three criteria: ΔH per mole, activation energy (Ea), and Ea for the reverse reaction.
  • Calculate Ea(rev) for both fuels and include working.
  • Use a named Australian context (Karratha LNG facility) to justify your recommendation.
  • Reach an evidence-based judgement identifying which fuel is preferred and why, including one practical limitation of your choice.
Plan first: define ΔH → compare Ea → calculate Ea(rev) → apply to Karratha scenario → justified recommendation with limitation.

2. Source critique — evaluate a student explanation (Band 5–6)

7 marks   Band 5–6

"An instant cold pack works because it contains chemicals that, when mixed, undergo an exothermic reaction. The reaction gets cold because it loses energy to the surrounding water molecules. The activation energy on the energy profile diagram shows the total height of the peak from the bottom of the graph — a higher peak means a faster reaction. The enthalpy change for the reverse reaction would be the same value but with the sign reversed, but this only applies if you double the coefficients."

— Year 11 student explanation, School Trial 2024

Q2. This student explanation contains multiple scientific errors. Identify each error precisely, explain the correct chemistry using lesson concepts, and rewrite the explanation as a scientifically accurate paragraph. In your response:

  • Identify and correct each discrete error (there are at least four).
  • For each correction, reference the specific lesson concept (e.g. “Card 02: Exothermic vs Endothermic”).
  • Write a corrected paragraph of 4–6 sentences at the end.
Stuck? Count the errors systematically: (1) exo/endo classification, (2) what “gets cold” means, (3) the Ea measurement rule, (4) Ea and reaction rate relationship, (5) the condition for reversing ΔH.
Answers — Do not peek before attempting

Q1 — Sample Band 6 response (8 marks), annotated

Enthalpy change (ΔH) is the heat energy exchanged between the system and surroundings at constant pressure, equal to H(products) − H(reactants). A negative ΔH indicates that energy flows from the system to the surroundings (exothermic). [1 — definition + sign interpretation]

Both combustions are exothermic (ΔH < 0). Propane releases more energy per mole (−2220 kJ mol−1) than methane (−890 kJ mol−1), so more heat is available per mole of propane burned — an advantage for a generator needing sustained output. [1 — ΔH comparison criterion] The activation energies are similar: methane Ea = 420 kJ mol−1; propane Ea = 440 kJ mol−1. Both fuels require comparable energy input to initiate combustion — ignition difficulty is not a significant differentiating factor. [1 — Ea comparison criterion]

Ea(rev) for methane: Ea(rev) = Ea(fwd) − ΔH = 420 − (−890) = 1310 kJ mol−1. Ea(rev) for propane: 440 − (−2220) = 2660 kJ mol−1. The very large reverse Ea values confirm both combustions are highly thermodynamically favoured in the forward direction — neither reaction will spontaneously reverse under generator operating conditions. [1 — Ea(rev) calculations, both correct] [1 — interpretation of reverse Ea]

In the Karratha LNG context, methane (natural gas) is the fuel produced on-site and already piped to facility infrastructure. Using propane would require separate transport and storage, adding logistical complexity and cost in a remote coastal environment. [1 — Australian context applied]

Recommendation: methane is the preferred fuel for the Karratha emergency generator. Although propane releases more energy per mole, methane is produced and stored on-site, has essentially the same activation energy (only 20 kJ mol−1 lower Ea, a negligible ignition difference), and avoids introducing a second fuel type into an already safety-critical facility. A practical limitation is that methane’s lower energy density per mole means a larger volume of gas must be burned to deliver the same energy output as propane — storage tank sizing must account for this. [1 — justified recommendation] [1 — practical limitation identified]

Marking criteria (8 marks):

  • 1 mark — Defines ΔH correctly and states that its sign indicates direction of energy flow (negative = exothermic).
  • 1 mark — Compares ΔH per mole: propane releases more energy per mole (−2220 vs −890 kJ mol−1).
  • 1 mark — Compares Ea(fwd): values are similar (420 vs 440); ignition difficulty is comparable.
  • 1 mark — Calculates Ea(rev) for methane correctly (1310 kJ mol−1).
  • 1 mark — Calculates Ea(rev) for propane correctly (2660 kJ mol−1).
  • 1 mark — Interprets the large reverse Ea values: combustion is thermodynamically irreversible under operating conditions; the high reverse Ea confirms forward reaction strongly favoured.
  • 1 mark — Names the Karratha LNG context and applies it to the recommendation (on-site availability, logistical argument).
  • 1 mark — Reaches a justified, evidence-based recommendation that identifies a practical limitation (e.g. lower energy density of methane means larger gas volume needed).

Q2 — Source critique sample response (7 marks), annotated

Error 1: “exothermic reaction” — cold packs use endothermic reactions (dissolution of NH4NO3). ΔH > 0. [1 — correct identification & correction; Card 02]

Error 2: “The reaction gets cold” — the reaction does not “get cold”; the surroundings (including your hand) cool down because heat flows from the surroundings into the endothermic system. Precise language: system and surroundings must be distinguished. [1 — system/surroundings language; Card 02 common error callout]

Error 3: “Ea is the total height of the peak from the bottom of the graph” — Ea is measured from the reactant enthalpy level to the peak, not from the x-axis or absolute zero. The position of the reactant level on the y-axis is arbitrary; only differences between levels are meaningful. [1 — Ea measurement rule; Card 02 diagram section]

Error 4: “A higher peak means a faster reaction” — a higher Ea means a slower reaction (fewer collisions have sufficient energy to overcome a larger barrier). Higher Ea = slower, not faster. [1 — Ea and rate relationship; Card 02 + Module 3 connection]

Error 5: “only applies if you double the coefficients” — the sign reversal when reversing ΔH applies to any reversal of the equation, regardless of coefficients. The coefficients affect the magnitude (scaling rule), but the sign reversal is simply a consequence of reversing the reaction direction. [1 — thermochemical equation rules; Card 03]

Corrected paragraph (2 marks for accuracy and precision): An instant cold pack works because it contains ammonium nitrate, which undergoes an endothermic dissolution when mixed with water (ΔH > 0). In an endothermic reaction, energy flows from the surroundings into the system, so the surroundings (including the injured area) cool down — the reaction absorbs heat from your hand. On an energy profile diagram, the activation energy is measured from the reactant enthalpy level up to the transition state peak — not from the bottom of the graph. A larger activation energy means fewer collisions have sufficient energy to react, so the reaction is slower. Reversing a thermochemical equation always flips the sign of ΔH; scaling the coefficients changes the magnitude. These two rules are independent.

Marking criteria (7 marks):

  • 1 mark — Identifies and corrects Error 1: cold packs use endothermic, not exothermic, reactions.
  • 1 mark — Identifies and corrects Error 2: the surroundings cool down (not “the reaction gets cold”); precise system/surroundings language.
  • 1 mark — Identifies and corrects Error 3: Ea is from the reactant level to the peak, not from the x-axis.
  • 1 mark — Identifies and corrects Error 4: higher Ea = slower reaction, not faster.
  • 1 mark — Identifies and corrects Error 5: sign reversal applies to any reversal of the equation, not only when coefficients are doubled.
  • 2 marks — Corrected paragraph: 1 mark for scientific accuracy (all corrections integrated); 1 mark for precision and appropriate lesson terminology (ΔH, endothermic, activation energy, surroundings, thermochemical equation).