Chemistry · Year 11 · Module 2 · Lesson 11
HSC Exam Practice
Stoichiometry — Mole Ratios
Short answer
1.Short answer
Define stoichiometry and explain how a balanced chemical equation enables stoichiometric calculations.
Distinguish between a coefficient and a subscript in a chemical equation. Explain why only coefficients — never subscripts — may be changed when balancing.
Explain why the Law of Conservation of Mass requires a chemical equation to be balanced, with reference to what happens to atoms during a chemical reaction.
For the equation 2Al + 3Cl2 → 2AlCl3, identify the mole ratio of Al : Cl2 : AlCl3. If 0.900 mol of Al reacts completely, calculate the moles of Cl2 required and the moles of AlCl3 produced. Show all working.
Account for the fact that the mole ratio in a balanced equation holds at any scale of reaction, whether in a laboratory test tube or an industrial reactor.
Outline why a student who claims “in 2H2O, the mole ratio of H2 to O is 2 : 1 because the subscript in H2 is 2 and oxygen has no subscript” is incorrect. Identify the specific conceptual error and state the correct way to determine the mole ratio for a reaction.
Data response
2.Data response — ammonia synthesis via the Haber process
A chemist monitors the Haber process N2(g) + 3H2(g) → 2NH3(g) in a sealed reactor. The graph below shows n(NH3) produced as a function of time at constant temperature and pressure, starting with 10.0 mol N2 and 30.0 mol H2.
(a) Describe the trend in n(NH3) production shown in the graph. Use the graph to estimate at what time the reaction effectively reaches completion. (2 marks)
(b) The plateau occurs at approximately 18.0 mol NH3. Calculate the moles of N2 and H2 consumed to produce 18.0 mol NH3. Use the mole ratio formula and show working. (3 marks)
(c) Given that the reaction started with 10.0 mol N2 and the data shows only 9.0 mol N2 was consumed (plateau at 18.0 mol NH3), calculate the percentage of N2 that reacted. Comment on whether the Law of Conservation of Mass is satisfied by the stoichiometry of this reaction. (3 marks)
Extended response
3.Extended response
Evaluate the claim that “the mole ratio in a balanced equation is simply a mathematical convenience with no physical meaning.” In your response, analyse what mole ratios represent at the particle level, discuss how they are used in stoichiometric calculations, and assess their significance in both laboratory and industrial chemistry contexts. Refer to at least two named reactions.
Chemistry · Year 11 · Module 2 · Lesson 11
Answer Key & Marking Guidelines
Section 1 · Short answer · 3 marks · Band 3
Sample response. Stoichiometry is the branch of chemistry that uses balanced equations to calculate quantities of reactants and products involved in chemical reactions. A balanced equation provides the mole ratio — the coefficients indicate the exact proportions in which substances react and are produced. These ratios act as conversion factors, allowing the moles of any species to be calculated from the known moles of any other species in the reaction.
Marking notes. 1 mark for a correct definition of stoichiometry referencing balanced equations and quantities. 1 mark for identifying that coefficients provide the mole ratio. 1 mark for explaining that the mole ratio is used as a conversion factor to relate moles of one species to another.
Section 1 · Short answer · 4 marks · Band 3–4
Sample response. A coefficient is the large number written in front of a chemical formula, indicating the number of moles of that substance in the reaction (e.g. the 2 in 2HCl). A subscript is the small number written within the formula indicating the number of atoms of that element in one formula unit (e.g. the 2 in H2O). Coefficients can be changed when balancing because doing so only adjusts the number of moles of a substance without altering its chemical identity. Subscripts cannot be changed because doing so produces an entirely different substance — for example, changing H2O to H2O2 produces hydrogen peroxide, not water.
Marking notes. 1 mark for a correct definition of coefficient (moles of substance, large number in front). 1 mark for a correct definition of subscript (atoms per formula unit, small number inside formula). 1 mark for explaining why coefficients can be changed (adjusts quantity only, not identity). 1 mark for explaining why subscripts cannot be changed (changes the chemical identity/formula of the substance).
Section 1 · Short answer · 3 marks · Band 3–4
Sample response. The Law of Conservation of Mass states that atoms are rearranged but never created or destroyed in a chemical reaction. This means the total number of each type of atom must be the same on both sides of the equation. A balanced equation ensures this condition is met. If an equation is unbalanced, it implies atoms have been created or destroyed, which would violate the law and misrepresent the actual reaction.
Marking notes. 1 mark for stating that atoms are rearranged but not created or destroyed. 1 mark for linking this to requiring equal atom counts on both sides. 1 mark for stating that an unbalanced equation implies a violation of conservation of mass.
Section 1 · Short answer · 3 marks · Band 3
Sample response. Mole ratio Al : Cl2 : AlCl3 = 2 : 3 : 2 (from coefficients). n(Cl2) = 0.900 × (3÷2) = 1.35 mol. n(AlCl3) = 0.900 × (2÷2) = 0.900 mol.
Marking notes. 1 mark for correctly stating the mole ratio 2:3:2. 1 mark for correct calculation of n(Cl2) = 1.35 mol with working. 1 mark for correct calculation of n(AlCl3) = 0.900 mol with working.
Section 1 · Short answer · 2 marks · Band 3
Sample response. The mole ratio is determined solely by the coefficients in the balanced equation, which reflect the fixed proportions in which atoms combine to form products. These proportions arise from the fixed atomic composition of the reactants and products and do not change with scale. Whether 1 mol or 1000 mol of reactant is used, the ratio of moles of one species to another remains constant because it is a property of the chemical reaction itself, not of the quantity of material.
Marking notes. 1 mark for explaining that the mole ratio comes from the coefficients/atomic composition, not from the quantity of material. 1 mark for stating that the ratio is scale-independent because it is a fixed property of the reaction.
Section 1 · Short answer · 3 marks · Band 4
Sample response. The student’s error is using subscripts (the small numbers inside the formula H2) instead of coefficients (the large numbers in front of formulas) to determine the mole ratio. In 2H2O, the subscript 2 in H2 tells you there are two hydrogen atoms in one water molecule — it says nothing about the mole ratio between H2 and O2 in any reaction. The correct way to determine a mole ratio is to first write the balanced equation for the reaction in question (e.g. 2H2 + O2 → 2H2O), then read the coefficients: the mole ratio H2 : O2 = 2 : 1.
Marking notes. 1 mark for identifying the specific error (using subscripts instead of coefficients). 1 mark for explaining what the subscript 2 in H2 actually means (atom count within one molecule, not a mole ratio). 1 mark for stating the correct method (write the balanced equation; read the coefficients).
Section 2 · Data response · 8 marks · Band 4–5
Sample response (a). n(NH3) increases rapidly from 0 mol at t = 0, with the steepest rate in the first 4–6 minutes [1]. The rate slows progressively and the curve levels off (plateaus) at approximately 18 mol NH3 by about 12 minutes, at which point the reaction has effectively reached completion [1].
Sample response (b). Ratio N2 : NH3 = 1 : 2. n(N2) consumed = 18.0 × (1÷2) = 9.00 mol [1]. Ratio H2 : NH3 = 3 : 2. n(H2) consumed = 18.0 × (3÷2) = 27.0 mol [1]. Check: started with 10.0 mol N2 and 30.0 mol H2; 9.00 mol N2 consumed (1.00 mol remaining); 27.0 mol H2 consumed (3.00 mol remaining). Both consistent with stoichiometric ratio [1].
Sample response (c). % N2 reacted = (9.00 ÷ 10.0) × 100 = 90% [1]. Conservation of mass: total atoms in = N2 + H2 consumed = 9.00 mol N2 × 28 g/mol + 27.0 mol H2 × 2 g/mol = 252 + 54 = 306 g of atoms. 18.0 mol NH3 × 17 g/mol = 306 g [1]. The total mass of products equals the total mass of reactants consumed, confirming the Law of Conservation of Mass is satisfied [1].
Marking notes. Part (a): 1 mark for correct description of trend (rapid increase then plateau); 1 mark for identifying ~12 min as the time at which the reaction effectively reaches completion. Part (b): 1 mark for n(N2) = 9.00 mol with working; 1 mark for n(H2) = 27.0 mol with working; 1 mark for checking consistency with initial quantities. Part (c): 1 mark for % = 90%; 1 mark for conservation of mass calculation (mass in = mass out); 1 mark for explicitly confirming conservation of mass is satisfied.
Section 3 · Extended response · 7 marks · Band 5–6
Sample response. The claim that mole ratios are “merely a mathematical convenience” is incorrect and misrepresents the physical basis of stoichiometry. At the particle level, the mole ratio reflects the fixed proportions in which atoms and molecules combine, as dictated by conservation of mass and the Law of Definite Proportions. For example, in 2H2(g) + O2(g) → 2H2O(g), the 2 : 1 : 2 ratio means that at the molecular level, every single O2 molecule requires exactly two H2 molecules to form two H2O molecules. The ratio arises from the electronic structure and bonding requirements of the atoms — it is physically determined, not arbitrary. In stoichiometric calculations, the mole ratio serves as a conversion factor: given n(H2) = 4.00 mol, n(H2O) = 4.00 × (2÷2) = 4.00 mol. This calculation is only meaningful because the ratio reflects an underlying physical reality about how atoms combine. In the Haber process (N2 + 3H2 → 2NH3), knowing the 1 : 3 : 2 mole ratio is critical for industrial planning: engineers use it to determine the stoichiometric feedstock quantities and to calculate yield per pass. If the ratio were merely a convention, there would be no basis for predicting that 100 mol N2 requires exactly 300 mol H2. The stoichiometry enforces real physical constraints. A second example from Australian industry is the thermite reaction (3Fe3O4 + 8Al → 9Fe + 4Al2O3) used in railway weld repair. The mole ratio determines exactly how much Al powder is packed with the iron oxide, directly controlling the yield of molten iron produced. Too little Al would leave unreacted oxide; too much would waste material. The claim is therefore false: the mole ratio has direct physical meaning at both particle and macroscopic scales, and its application in stoichiometric calculations reflects real chemical constraints, not mathematical convenience.
Marking criteria (7 marks). [1] Correctly refutes the claim by stating the physical basis of mole ratios (atomic/molecular combining proportions from conservation of mass and definite proportions). [1] Explains the particle-level meaning of the ratio for a named reaction (e.g. 2H2 + O2 → 2H2O: each O2 needs two H2 molecules). [1] Demonstrates correct use of a mole ratio in a stoichiometric calculation (formula applied with correct values). [1] First named industrial or significant reaction with the mole ratio applied correctly (Haber process or equivalent). [1] Second named reaction with mole ratio correctly applied (thermite, combustion, neutralisation — any valid second reaction). [1] Discusses why the ratio is scale-independent and physically determined, not arbitrary. [1] Reaches an explicit evaluative judgement clearly stating the claim is incorrect and integrating both particle-level and macroscopic evidence.