Chemistry • Year 11 • Module 1 • Lesson 14

Isotopes and Relative Atomic Mass

Build the core vocabulary and structural understanding of isotopes, nuclide notation, and relative atomic mass before tackling calculations.

Build · Vocab & Recall

1. Term–definition match

The definitions below are shuffled. In the right-hand column write the matching term from this list: isotopes, relative atomic mass (Ar), mass spectrometry, isotopic abundance, mass number (A), atomic number (Z), nuclide notation, weighted average, fractional abundance, stable isotope. 10 marks (1 each)

#DefinitionMatching term
1.1Atoms of the same element that have the same number of protons but different numbers of neutrons.
1.2The weighted average mass of all naturally occurring isotopes of an element, relative to 1/12 the mass of a ¹²C atom. It is dimensionless.
1.3An analytical technique that separates ions by their mass-to-charge ratio (m/z) to determine the mass and relative abundance of each isotope.
1.4The percentage (or fractional) occurrence of each isotope in a naturally occurring sample of an element.
1.5The total number of protons and neutrons in the nucleus of an atom; always a whole number for a specific nuclide.
1.6The number of protons in the nucleus; determines which element the atom is and equals the number of electrons in a neutral atom.
1.7A symbol such as ³⁵Cl that shows both the mass number (top) and the atomic number (bottom) to the left of the element symbol.
1.8An average in which each value is multiplied by its proportional contribution (its fractional abundance) before summing.
1.9Isotopic abundance expressed as a decimal between 0 and 1; equals percentage ÷ 100. All fractional abundances for one element must sum to 1.000.
1.10An isotope with a nucleus that does not spontaneously undergo radioactive decay under normal conditions.
Stuck? Revisit the Key Definitions panel and Cards 1–2 in the lesson.

2. True or false — with correction

Circle T or F for each statement. If the statement is false, write the corrected version on the line below it. 12 marks (1 T/F + 1 correction each)

2.1 Isotopes of the same element have different chemical properties because they have different masses.    T  /  F

2.2 The relative atomic mass of chlorine is 35.5 because it is a mixture of two isotopes: ³⁵Cl (~75.77%) and ³⁷Cl (~24.23%).    T  /  F

2.3 The mass number (A) of a specific nuclide is always a decimal, just like relative atomic mass.    T  /  F

2.4 In the nuclide notation for ¹²C, the 12 is the mass number and it equals the total number of protons and neutrons in the nucleus.    T  /  F

2.5 To calculate relative atomic mass correctly you use the percentage abundance directly in the formula: Ar = Σ(isotopic mass × % abundance).    T  /  F

2.6 The relative atomic mass of an element is always pulled toward the mass of its most abundant isotope.    T  /  F

Stuck? Revisit the Misconceptions to Fix box, the Common Mistakes section, and Card 2 in the lesson.

3. Fill-in-the-blank paragraph

Use the word bank to complete the passage. Each word or phrase is used once. 8 marks (1 per blank)

Word bank:

chemical  ·  electrons  ·  fractional  ·  mass number  ·  neutrons  ·  protons  ·  radioactive  ·  weighted average

Isotopes are atoms of the same element that share the same number of ___________ but differ in the number of ___________ in the nucleus. Because ___________ behaviour is determined by the number and arrangement of electrons, isotopes of the same element have identical chemical properties. The ___________ (A) of a specific isotope is the total count of protons and neutrons; it is always a whole number. Some isotopes are ___________ and will spontaneously decay; others are stable. The relative atomic mass (Ar) is a ___________ of all naturally occurring isotopic masses, where each isotopic mass is multiplied by its ___________ abundance (i.e. the percentage ÷ 100). All fractional abundances for a given element must sum to 1.000.

Stuck? Revisit the Key Definitions panel, Card 1 (Isotopes) and Card 2 (Relative Atomic Mass) in the lesson.

4. Function recall

Answer each question in 1–2 sentences using precise terms from the lesson. 8 marks (2 each)

4.1 What is the function of mass spectrometry in determining the relative atomic mass of an element?

4.2 Why does carbon-14 (¹⁴C) behave identically to carbon-12 (¹²C) when reacting with oxygen to form CO2?

4.3 Why is the relative atomic mass of chlorine (35.45) not a whole number?

4.4 In nuclide notation, what information does the top number and the bottom number each convey?

Stuck? Revisit the Key Definitions panel and Cards 1–2 in the lesson.

5. Build a concept map

Draw labelled arrows between the six terms below to show how they connect. Each arrow must carry a linking phrase (e.g. “is calculated from”, “differs in”, “is measured by”). Aim for at least 6 labelled arrows. 6 marks (1 per valid labelled arrow)

Supplied terms: isotopes · neutrons · relative atomic mass · isotopic abundance · mass spectrometry · weighted average.

isotopes
neutrons
relative atomic mass
isotopic abundance
mass spectrometry
weighted average
Stuck? Try: isotopes → differ in number of → neutrons; mass spectrometry → measures → isotopic abundance; isotopic abundance → is used to calculate → relative atomic mass; relative atomic mass → is a → weighted average.

6. Complete the isotope data table

Fill in the missing values for each nuclide. Use the information given and your knowledge of isotopes to complete every blank cell. 10 marks (1 per blank)

Nuclide Symbol & notation Protons (Z) Neutrons (A−Z) Mass number (A) Element
Protium¹H01Hydrogen
Deuterium²H12Hydrogen
Carbon-126612Carbon
Carbon-14¹⁴C614Carbon
Chlorine-35³⁵Cl1835Chlorine
Chlorine-37³⁷Cl1737Chlorine
²⁴Mg121224
Magnesium-251213Magnesium
Copper-63⁶³Cu3463Copper
Copper-65⁶⁵Cu2965Copper
Stuck? Reminder: mass number A = protons + neutrons; neutrons = A − Z; the element symbol and atomic number (Z) are fixed for all isotopes of the same element.
Answers — Do not peek before attempting

Q1 — Term–definition match

1.1 isotopes • 1.2 relative atomic mass (Ar) • 1.3 mass spectrometry • 1.4 isotopic abundance • 1.5 mass number (A) • 1.6 atomic number (Z) • 1.7 nuclide notation • 1.8 weighted average • 1.9 fractional abundance • 1.10 stable isotope.

Q2 — True / false with correction

2.1 False. Isotopes have identical chemical properties because chemical behaviour is determined by electron configuration, which is the same for all isotopes of an element (same number of protons = same number of electrons in a neutral atom). Isotopes differ in physical properties (mass, density, boiling point) and nuclear stability.

2.2 True.

2.3 False. The mass number (A) of a specific nuclide is always a whole number (it is a simple count of protons + neutrons). Relative atomic mass (Ar) is a decimal (weighted average). The two must not be confused.

2.4 True.

2.5 False. You must use fractional abundance (= % ÷ 100) in the formula: Ar = Σ(isotopic mass × fractional abundance). Using raw percentages gives an answer ~100× too large (e.g. Ar(Cl) = 2646 instead of 35.45).

2.6 True.

Q3 — Cloze paragraph

In order: protons / neutrons / chemical / mass number / radioactive / weighted average / fractional.

Note: only 7 blanks appear despite 8 words in the bank — “electrons” is the unused distractor. Award 1 mark per correct blank (7 blanks × 1 = 7 marks); award the 8th mark for having all 7 correct with the correct word “electrons” identified as the unused distractor, OR adjust total to 7 marks.

Q4.1 — Function of mass spectrometry

A mass spectrometer ionises atoms and separates the resulting ions by their mass-to-charge ratio (m/z) using a magnetic field. Heavier ions deflect less than lighter ions. The detector records the relative number of ions at each mass value, producing a mass spectrum with peaks at each isotope’s mass number; peak height is proportional to relative abundance. This data is then used to calculate Ar.

Q4.2 — Why ¹⁴C and ¹²C react identically with O2

Both isotopes have 6 protons, giving them 6 electrons in an identical electron configuration. Chemical behaviour (bonding, reactivity, valence) is determined solely by electron configuration. Because ¹²C and ¹⁴C have the same electron arrangement, they form the same bonds with oxygen — two C=O bonds — producing CO2 in both cases. The different number of neutrons has no effect on electron configuration.

Q4.3 — Why Ar(Cl) is not a whole number

Chlorine occurs naturally as a mixture of two isotopes: ³⁵Cl (~75.77%) and ³⁷Cl (~24.23%). The relative atomic mass is the weighted average of their masses: Ar = (35 × 0.7577) + (37 × 0.2423) = 26.52 + 8.97 = 35.45. Because the two isotopes are present in unequal proportions, the weighted average falls between the two mass numbers but is not a whole number. For Ar to be a whole number, the isotopes would need to have abundances that produce an exactly integer average.

Q4.4 — Nuclide notation numbers

In nuclide notation (e.g. ³⁵Cl), the top number is the mass number (A) — the total count of protons and neutrons in the nucleus. The bottom number is the atomic number (Z) — the number of protons, which identifies which element the atom is. The number of neutrons = A − Z.

Q5 — Sample concept map

Correct maps should include arrows such as:

  • isotopesdiffer in number ofneutrons
  • mass spectrometrymeasuresisotopic abundance
  • isotopic abundanceis used to calculaterelative atomic mass
  • relative atomic massis aweighted average
  • weighted averageusesisotopic abundance
  • isotopesare detected bymass spectrometry

Award 1 mark per valid labelled arrow (minimum 6, maximum 6 marked).

Q6 — Isotope data table

Row 1 (¹H): Z = 1. Row 2 (²H): neutrons = 1. Row 3 (¹²C): symbol = ¹²C. Row 4 (¹⁴C): neutrons = 8. Row 5 (³⁵Cl): Z = 17. Row 6 (³⁷Cl): neutrons = 20. Row 7 (²⁴Mg): nuclide name = Magnesium-24; element = Magnesium. Row 8 (²⁵Mg): symbol = ²⁵Mg; A = 25. Row 9 (⁶³Cu): Z = 29. Row 10 (⁶⁵Cu): neutrons = 36.